XLS《学校基表》

"参照标准详见附件2实验教学仪器及《福建省初中理科教学仪器配备标准(试行)》第二种方案配备要求.初中数学、初中劳动与技术实践室、初中图书室配套设施有缺口的并入该栏填报", "22",,

"专任教师","人"62","初中化学实验室"62=63" "23",,

"在校学生数","人"63","全校是否达标"63=64+65" "24",,

"其中:寄宿生","人"64","达标教室","间",,

"同60", "25",,

"在校生中农村留守儿童","人"65","仪器设备","台件套",,

"同61(不含数学、劳动室等部分)", "26",,

"寄宿生中的农村留守儿童","人"66","初中生物实验室"66=67" "27","校舍单体数",,

"个",,

,"27=28","67","全校是否达标"67=68+69" "28","

一、校舍建筑面积",,

"m2","28=29+35","28=29+35","28=29+35","68","达标教室","间",,

"同60", "29","

(一)教学及辅助用房",,

"m2","29=30+..+34","29=30+..+34","29=30+..+34","69","仪器设备","台件套",,

"同61(不含数学、劳动室等部分)", "30","其中:普通教室",,

"m2",,

"参照标准详见附件2",,

"70","初中地理实验室"70=71" "31","实验室",,

"m2",,

"参照标准详见附件2",,

"71","全校是否达标"71=72+73" "32","图书室",,

"m2",,

"参照标准详见附件2",,

"72","达标教室","间",,

"同60", "33","计算机室",,

"m2",,

"参照标准详见附件2",,

"73","仪器设备","台件套",,

"同61(不含数学、劳动室等部分)", "34","其他",,

"m2",,

"参照标准详见附件2",,

"74","

八、音乐器材","台件套",,

"参照标准详见附件2体音美教室", "35","

(二)生活用房",,

"m2","35=36+..+41","35=36+..+41","35=36+..+41","75","

九、体育器材","台件套",,

"参照标准详见附件2体音美教室", "36","其中:学生宿舍",,

"m2",,

"参照标准详见附件2",,

"76","

十、美术器材","台件套",,

"参照标准详见附件2体音美教室",,

,,

,,

"37","食堂或伙房","食堂或伙房","m2",,

"参照标准详见附件2",,

"77","十

一、信息化装备"77=78+79+80" "38","锅炉房(开水房)",,

"m2",,

"参照标准详见附件2",,

"78","其中:计算机","台",,

"参照标准详见附件2信息技术装备", "39","厕所",,

"m2",,

"参照标准详见附件2",,

"79","网络多媒体教室","间",,

"参照标准详见附件2信息技术装备(计算机室的配套设施也统计在内)", "40","浴室",,

"m2",,

"参照标准详见附件2",,

"80","网络宽带接入","有或无",,

"参照标准详见附件2信息技术装备", "填表说明: ,"1.此表由学校按照《福建省"义务教育标准化学校"建设基本标准》(小学、初中、一贯制学校)、《福建省农村小学教学点基本办学条件》(农村小学教学点),结合学校满足基本办学需要填写,每校填一张.一贯制学校分别填写对应的小学阶段和初中阶段部分;

完全中学填写对应的初中部. ,"2.学校(机构)代码:是指由教育部按照国家标准及编码规则编制,赋予每一个学校在全国范围内唯一的、始终不变的10位识别代码. ,"3.寄宿制形式:1-全部寄宿;

2-部分寄宿;

3-无寄宿. ,"4.数据项B

6、B7为通过建设拟减少的大班额数. ,"5.生活用房不包括教师宿舍. ,"6.运动场地要根据当地实际,依据地形地貌因地制宜建设,其他体育设施设备的配备也要符合地方特点. ,"7.57-76按照国家和省级相关仪器配备标准填写.填报任务需求时,对符合生均公用经费开支的低值易耗品、零星维修支出等支出项目,不纳入填报范围.学校要列出每一台、件、套的具体物品清单,交由县级教育部门保存备查. ,"8.学校是否达标栏,由学校根据《福建省"义务教育标准化学校"建设基本标准》,对本校相关实验设施和仪器是否达标作出判断,填是或否.达标教室是指实验室中教学设施的达标情况,包括演示台、实验台、准备台、电源、水源等. ,"9.资金需求(C)=需求(B)*单价" ,"10.表内关系:数据项(A、B)5=15+21;