编辑: hyszqmzc 2016-03-22
"施工临时用电计算KF002",,

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一、计算参数",,

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, "施工动力设备用电∑Pc",,

,"100","kW",,

, "室内照明设备用电∑Pa",,

,"5","kW",,

, "室外照明设备用电∑Pb",,

,"5","kW",,

, ,,

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, "

二、施工总用电量计算",,

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, ,"P=1.

1*(K1∑Pc+K2∑Pa+K3∑Pb)=",,

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"92.4","kW" "其中:","P:计算用电量,即供电设备总需要容量",,

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,"K1:全部施工用电设备同时使用系数",,

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"0.75",,

,"K2:室内照明设备同时使用系数",,

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"0.800000610351563",,

,"K3:室外照明设备同时使用系数",,

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"1",,

,"1.1:用电不均匀系数",,

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, "或: ,"P=1.24*K1∑Pc=",,

"93","kW",,

, "其中:","P:计算用电量,即供电设备总需要容量",,

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,"K1:全部施工用电设备同时使用系数",,

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"0.75",,

,"施工用电占总用电量的90%,室内外照明占总用电量的10% ,,

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, "

三、配电导线截面计算",,

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, "线路1",,

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1、按导线的允许电流选择",,

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, ,"Il=1000∑P/(31/2*Ul*cosφ)=",,

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"222.836946003013","A" "其中:","∑P:各段线路负荷计算功率",,

,"110","kW",,

,"Il:线路工作电流值",,

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,"Ul:线路工作电压值",,

,"三相四线制Ul=",,

"380","V" ,"cosφ:用电设备功率因数,一般建筑工地取",,

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,"0.75" "查表得导线截面S为:",,

"50","mm2",,

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"

2、按导线的允许电压降校核",,

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, ,"ε=∑M/(C*S)=∑P*L/(C*S)=",,

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"0.857142857142857","%" ,"ε","≤","[ε]=","7","%",,

"其中:","ε:导线电压降",,

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,"L:各段线路长度",,

"30","m",,

, ,"∑M:各段线路负荷矩(kW・m)",,

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"∑M=∑P・L",,

,"S:导线截面",,

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,"C:材料内部系数,根据线路电压和电流种类查表取用",,

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"77" ,"[ε]:工地临时网路允许电压降",,

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"则导线截面为: ,"S=∑P*L/(C*[ε])=",,

,"6.12244897959184","mm2",,

"

3、按导线机械强度校核",,

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, "查表导线满足按机械强度所允许的最小截面",,

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, "则最终确定导线截面为:",,

,"50","mm2",,

, ,,

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, "线路2",,

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, "

1、按导线的允许电流选择",,

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, ,"Il=1000∑P/(31/2*Ul*cosφ)=",,

,,

"222.836946003013","A" "其中:","∑P:各段线路负荷计算功率",,

,"110","kW",,

,"Il:线路工作电流值",,

,,

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,"Ul:线路工作电压值",,

,"三相五线制Ul=",,

"380","V" ,"cosφ:用电设备功率因数,一般建筑工地取",,

,,

,"0.75" "查表得导线截面S为:",,

"50","mm2",,

,,

"

2、按导线的允许电压降校核",,

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, ,"ε=∑M/(C*S)=∑P*L/(C*S)=",,

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"0.857142857142857","%" ,"ε","≤","[ε]=","7","%",,

"其中:","ε:导线电压降",,

,,

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,"L:各段线路长度",,

"30","m",,

, ,"∑M:各段线路负荷矩(kW・m)",,

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"∑M=∑P・L",,

,"S:导线截面",,

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,"C:材料内部系数,根据线路电压和电流种类查表取用",,

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"77" ,"[ε]:工地临时网路允许电压降",,

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"则导线截面为: ,"S=∑P*L/(C*[ε])=",,

,"6.12244897959184","mm2",,

"

3、按导线机械强度校核",,

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