DOC《课后习题》

3、面向过程的C实现 这是 csdn 算法论坛前版主海星的代码,程序非常简练、精致: #include #include #include using namespace std;

const double PRECISION = 1E-6;

const int COUNT_OF_NUMBER = 4;

const int NUMBER_TO_BE_CAL = 24;

double number[COUNT_OF_NUMBER];

string expression[COUNT_OF_NUMBER];

bool Search(int n) { if (n == 1) { if ( fabs(number[0] - NUMBER_TO_BE_CAL) < PRECISION ) { cout x;

number[i] = x;

itoa(x, buffer, 10);

expression[i] = buffer;

} if ( Search(COUNT_OF_NUMBER) ) { cout