编辑: 迷音桑 | 2013-07-22 |
第二章习题课 (2-12a) 2-12(b) 求: D(s) C(s) R(s) C(s) R(s) Gn + + D(s) 解: D(s)=0 G(s)= 1+G1G2H G1G2 G1 G2 H _ _ C(s) C(s) = R(s) 1+ 1+G1G2H G1G2 1+G1G2H G1G2 1+G1G2H+G1G2 G1G2 = R(s)=0 Gn + + D(s) 结构图变 换成: G1 G2 H - - C(s) Gn + + D(s) G1 G2 H - - C........